Fundamentals

This problem involves two related, but separate, quantiites: the amount of oxygen required to oxidize organic (waste) matter present in a body of water and the amount of DO available in the water to accomplish this task. The following sections explain the differential equation that governs each of these quantities.

>

DO and BOD

Dissolved oxygen (DO) is the amount of molecular oxygen dissolved in water and is one of the most important criteria in determining natural water quality. DO also affects wastewater treatment processes. The water's carrying capacity for DO, also known as the DO saturation level, depends on teh temperature of the water. DO saturation levels for different water temperatures can be measured with a DO meter; the values shown below are typical. Note that cooler water contains a greater concentration of dissolved oxygen than warmer water.

Table 5.1

[Maple Math]

>

Biochemical oxygen demand (BOD) is the amount of oxygen required to oxidize organic matter that is biochemically present in water and is, therefore, an indirect measure of organic water contamination. The greater the BOD, the greater the oxygen depletion in a stream or lake. It is a measure of waste strength insofar as it measures the oxygen-consuming property of waste in terms of oxygen that is biologically consumed. The BOD (in mg/L) after [Maple Math] days is

[Maple Math] ,

where [Maple Math] is the dilution bottle volume, [Maple Math] is the sample volume, and [Maple Math] is the sample dilution. (For example, the sample dilution would be 30 to 1 for a 10-mL wastewater sample placed inside a 300-mL bottle filled with dilution water.) The BOD is usually measured under controlled conditions, such as a temperature T=20C and darkness (to prevent oxygen-producing algae). [Maple Math] and [Maple Math] are the levels of dissolved oxygen in the sample bottle at the outset and after [Maple Math] days, respectively.

The rate of BOD consumption at each instant of time is proportional to the BOD remaining in the water supply at that time. That is, if [Maple Math] is the remaining BOD at time [Maple Math] , then

[Maple Math] ,

where the deoxygenation rate, [Maple Math] >0, (with units of 1/time) depends on a number of factors, including the number and type of microorganisms and the water temperature. Since [Maple Math] is positive, the organic contaminants decay exponentially with time. You will learn to use Maple to solve this differential equation in Chapter 6 (see the ftp site). The solution is

[Maple Math] ,

where [Maple Math] is the BOD remaining at the outset ( [Maple Math] ). Let [Maple Math] denote the amount of oxygen consumed through time [Maple Math] in mg/L. Assuming this is the only process affecting the oxygen content of the water sample, the total amount of oxygenwill be conserved. That is, for all [Maple Math] >=0, [Maple Math] =constant. Note that the constant can be determined, by measurement, at any instant of time; [Maple Math] , the ultimate BOD, is the total amount of BOD (waste) available for consumption (at [Maple Math] ). It is also the total amount of consumed oxygen when all the waste is depleted ( [Maple Math] -> [Maple Math] ).

>

The DO Sag Curve and the Streeter-Phelps Equation

The Streeter-Phelps equation accurately models the amount of DO in a stream after wastewater is discharge into it. This model follows the pollutant downstream as it travels at the stream velocity. When a pollutant is introduced into a water source, the DO typically decreases to a minimum before gradually recovering to the saturation level. The plot of the DO as a function of time is called the DO sag curve . There are two competing processes in this interaction: reaeration and deoxygenation . Reaeration adds molecular oxygen to the stream from the atmosphere (up to the saturation point); deoxygenation depletes the oxygen. Only the biochemically degradable microorganisms responsible for BOD are considered in the present analysis.

Let [Maple Math] denote the oxygenation rate (per day), [Maple Math] the reaeration rate (per day), [Maple Math] the oxygen deficit in the stream (the difference between the saturation and the actual DO level), and [Maple Math] the stream BOD remaining at time [Maple Math] . (Note that [Maple Math] and [Maple Math] are the same quantities discussed in the first part of this application.) The Streeter-Phelps model states that the rate of change of the stream oxygen deficit, [Maple Math] , increases in direct proportion to the stream BOD remaining, with proportionality constant given by the deoxygenation rate [Maple Math] , since the BOD is an indirect measure of organic water contamination itself. On the other hand, the rate of change of the oxygen deficit decreases in direct proportion to the deficit at time [Maple Math] , with proportionality constant given by the reaeration rate [Maple Math] . The Streeter-Phelps equation for the oxygen deficit represents both of these interacting processes:

[Maple Math] .

The solution to the Streeter-Phelps equation is

[Maple Math]

where [Maple Math] is the oxygen deficit when the pollutant first enters the stream ( [Maple Math] ). Suppose [Maple Math] =0.4/day, [Maple Math] =2.0/day, [Maple Math] =54.8 mg/L, and the initial DO level is 2.2 mg/L at a stream temperature of 21C.

The minimum of the DO sag cureve, which occurs at the sag time , is the time when the oxygen deficit is greatest (minimum DO) and represents the time of greatest stress to fish in the stream. Since the pollutant is flowing downstream at the stream velocity, it is necessary to identify both when and where the minimum is attained.

>