Comments on Problem 6.3.12
Homework
Math 555
-
We start with a continuous function
f : [0,1] &rarr R.
For each n &epsilon N,
define &phin , gn : [0,1] &rarr [0,1]
by
&phin (x) = xn
and gn (x) = f( xn) = [f &bull &phin ] (x) .
-
Next read about half of page 318 from our text:
from the start of section 8.1 to the end of the page.
-
Does our sequence { gn } above
converge pointwise
on [0,1] to a function
g (x) = lim n&rarr&infin gn (x) ?
Ok, to show me that you read my
blurb-in', on your homework,
answer this question
yes (and explicitly say what g is)
or no (and explain why not) or I have not idea.
-
Next read the whole of page 319.
Part (c) says that it is not necessarily true that
∫01
  [ lim n&rarr&infin gn (t) ] dt
   =   
lim n&rarr&infin
[ ∫01 gn (t) dt ]
   .
So do not make this mistake when doing problem 12.
It is kinda easy to see the difference between the
right and left -hand sides above but when you get in
the midst of a bunch of &epsilon's,
be careful of the dependency as to not make this mistake.
- Now do Problem 6.3.12.
Another warning:
we cannot assume, a prior, that
the limit, as n&rarr&infin,
of the sequence
{ ∫01 f(xn ) }
from R
exists.
Findable from URL:
http://www.math.sc.edu/~girardi/